5(2x-3)+7x=2/3(6x+12)-10

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Solution for 5(2x-3)+7x=2/3(6x+12)-10 equation: 



5(2x-3)+7x=2/3(6x+12)-10

We move all terms to the left:

5(2x-3)+7x-(2/3(6x+12)-10)=0



Domain of the equation: 3(6x+12)-10)!=0

x∈R



We add all the numbers together, and all the variables

7x+5(2x-3)-(2/3(6x+12)-10)=0

We multiply parentheses

7x+10x-(2/3(6x+12)-10)-15=0

We multiply all the terms by the denominator


7x*3(6x+12)-10)+10x*3(6x+12)-10)-(2-15*3(6x+12)-10)=0

We add all the numbers together, and all the variables

7x*3(6x+12)-10)+10x*3(6x+12)-10)-(2-15*3(6x=0

Wy multiply elements

21x^2(6-10)+10x*3(6x+12)-15*3(6x-10)-(2=0

We add all the numbers together, and all the variables

21x^2(-4)+10x*3(6x+12)-15*3(6x-10)-(2=0

We add all the numbers together, and all the variables

21x^2(-4)+10x*3(6x+12)-15*3(6x-10)=0

Wy multiply elements

21x^2(-4)+30x^2(6-45x(6=0

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