13c(38-c)=

Solution for 13c(38-c)= equation:

13c(38-c)=

We move all terms to the left:

13c(38-c)-()=0

We add all the numbers together, and all the variables

13c(-1c+38)-()=0

We add all the numbers together, and all the variables

13c(-1c+38)=0

We multiply parentheses

-13c^2+494c=0

a = -13; b = 494; c = 0;
Δ = b2-4ac
Δ = 4942-4·(-13)·0
Δ = 244036
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{244036}=494$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(494)-494}{2*-13}=\frac{-988}{-26}
=+38
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(494)+494}{2*-13}=\frac{0}{-26}
=0
$