(3x+4)+((5x2-1)+(2x+6))=

Solution for (3x+4)+((5x2-1)+(2x+6))= equation:

(3x+4)+((5x^2-1)+(2x+6))=

We move all terms to the left:

(3x+4)+((5x^2-1)+(2x+6))-()=0

We add all the numbers together, and all the variables

(3x+4)+((5x^2-1)+(2x+6))=0

We get rid of parentheses

3x+((5x^2-1)+(2x+6))+4=0


We calculate terms in parentheses: +((5x^2-1)+(2x+6)), so:

(5x^2-1)+(2x+6)

We get rid of parentheses

5x^2+2x-1+6

We add all the numbers together, and all the variables

5x^2+2x+5

Back to the equation:

+(5x^2+2x+5)


We get rid of parentheses

5x^2+3x+2x+5+4=0

We add all the numbers together, and all the variables

5x^2+5x+9=0

a = 5; b = 5; c = +9;
Δ = b2-4ac
Δ = 52-4·5·9
Δ = -155
Delta is less than zero, so there is no solution for the equation