13=4-2(x-4)+3x

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Solution for 13=4-2(x-4)+3x equation: 



13=4-2(x-4)+3x

We move all terms to the left:

13-(4-2(x-4)+3x)=0



We calculate terms in parentheses: -(4-2(x-4)+3x), so:

4-2(x-4)+3x

determiningTheFunctionDomain
-2(x-4)+3x+4

We add all the numbers together, and all the variables

3x-2(x-4)+4

We multiply parentheses

3x-2x+8+4

We add all the numbers together, and all the variables

x+12

Back to the equation:

-(x+12)



We get rid of parentheses

-x-12+13=0

We add all the numbers together, and all the variables

-1x+1=0

We move all terms containing x to the left, all other terms to the right

-x=-1

x=-1/-1

x=1

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