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(x-9)/(3x+2)=3
We move all terms to the left:
(x-9)/(3x+2)-(3)=0
Domain of the equation: (3x+2)!=0We multiply all the terms by the denominator
We move all terms containing x to the left, all other terms to the right
3x!=-2
x!=-2/3
x!=-2/3
x∈R
(x-9)-3*(3x+2)=0
We multiply parentheses
(x-9)-9x-6=0
We get rid of parentheses
x-9x-9-6=0
We add all the numbers together, and all the variables
-8x-15=0
We move all terms containing x to the left, all other terms to the right
-8x=15
x=15/-8
x=-1+7/8
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