13=4(c+2)-3

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Solution for 13=4(c+2)-3 equation: 



13=4(c+2)-3

We move all terms to the left:

13-(4(c+2)-3)=0



We calculate terms in parentheses: -(4(c+2)-3), so:

4(c+2)-3

We multiply parentheses

4c+8-3

We add all the numbers together, and all the variables

4c+5

Back to the equation:

-(4c+5)



We get rid of parentheses

-4c-5+13=0

We add all the numbers together, and all the variables

-4c+8=0

We move all terms containing c to the left, all other terms to the right

-4c=-8

c=-8/-4

c=+2

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