2x-5(x-3)=-8+4x-12

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Solution for 2x-5(x-3)=-8+4x-12 equation: 



2x-5(x-3)=-8+4x-12

We move all terms to the left:

2x-5(x-3)-(-8+4x-12)=0

We add all the numbers together, and all the variables

2x-5(x-3)-(4x-20)=0

We multiply parentheses

2x-5x-(4x-20)+15=0

We get rid of parentheses

2x-5x-4x+20+15=0

We add all the numbers together, and all the variables

-7x+35=0

We move all terms containing x to the left, all other terms to the right

-7x=-35

x=-35/-7

x=+5

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