13=2y+(-3)(y+4)

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Solution for 13=2y+(-3)(y+4) equation: 



13=2y+(-3)(y+4)

We move all terms to the left:

13-(2y+(-3)(y+4))=0

We multiply parentheses ..

-(2y+(-3y-12))+13=0



We calculate terms in parentheses: -(2y+(-3y-12)), so:

2y+(-3y-12)

We get rid of parentheses

2y-3y-12

We add all the numbers together, and all the variables

-1y-12

Back to the equation:

-(-1y-12)



We get rid of parentheses

1y+12+13=0

We add all the numbers together, and all the variables

y+25=0

We move all terms containing y to the left, all other terms to the right

y=-25

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