10(2x-5)=2(5x+7)

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Solution for 10(2x-5)=2(5x+7) equation: 



10(2x-5)=2(5x+7)

We move all terms to the left:

10(2x-5)-(2(5x+7))=0

We multiply parentheses

20x-(2(5x+7))-50=0



We calculate terms in parentheses: -(2(5x+7)), so:

2(5x+7)

We multiply parentheses

10x+14

Back to the equation:

-(10x+14)



We get rid of parentheses

20x-10x-14-50=0

We add all the numbers together, and all the variables

10x-64=0

We move all terms containing x to the left, all other terms to the right

10x=64

x=64/10

x=6+2/5

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