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13=1/6y+2y
We move all terms to the left:
13-(1/6y+2y)=0
Domain of the equation: 6y+2y)!=0We add all the numbers together, and all the variables
y∈R
-(+2y+1/6y)+13=0
We get rid of parentheses
-2y-1/6y+13=0
We multiply all the terms by the denominator
-2y*6y+13*6y-1=0
Wy multiply elements
-12y^2+78y-1=0
a = -12; b = 78; c = -1;
Δ = b2-4ac
Δ = 782-4·(-12)·(-1)
Δ = 6036
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{6036}=\sqrt{4*1509}=\sqrt{4}*\sqrt{1509}=2\sqrt{1509}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(78)-2\sqrt{1509}}{2*-12}=\frac{-78-2\sqrt{1509}}{-24} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(78)+2\sqrt{1509}}{2*-12}=\frac{-78+2\sqrt{1509}}{-24} $
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