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(12.25+x)x1.06=19.08
We move all terms to the left:
(12.25+x)x1.06-(19.08)=0
We add all the numbers together, and all the variables
(x+12.25)x1.06-(19.08)=0
We add all the numbers together, and all the variables
(x+12.25)x1.06-19.08=0
We multiply parentheses
x^2+12.25x-19.08=0
a = 1; b = 12.25; c = -19.08;
Δ = b2-4ac
Δ = 12.252-4·1·(-19.08)
Δ = 226.3825
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12.25)-\sqrt{226.3825}}{2*1}=\frac{-12.25-\sqrt{226.3825}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12.25)+\sqrt{226.3825}}{2*1}=\frac{-12.25+\sqrt{226.3825}}{2} $
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