135+128+(3x+31)+(4x+15)+(7x-64)+(5x-4)=x

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Solution for 135+128+(3x+31)+(4x+15)+(7x-64)+(5x-4)=x equation: 



135+128+(3x+31)+(4x+15)+(7x-64)+(5x-4)=x

We move all terms to the left:

135+128+(3x+31)+(4x+15)+(7x-64)+(5x-4)-(x)=0

We add all the numbers together, and all the variables

-1x+(3x+31)+(4x+15)+(7x-64)+(5x-4)+263=0

We get rid of parentheses

-1x+3x+4x+7x+5x+31+15-64-4+263=0

We add all the numbers together, and all the variables

18x+241=0

We move all terms containing x to the left, all other terms to the right

18x=-241

x=-241/18

x=-13+7/18

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