132=4(1+8k)

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Solution for 132=4(1+8k) equation:



132=4(1+8k)
We move all terms to the left:
132-(4(1+8k))=0
We add all the numbers together, and all the variables
-(4(8k+1))+132=0
We calculate terms in parentheses: -(4(8k+1)), so:
4(8k+1)
We multiply parentheses
32k+4
Back to the equation:
-(32k+4)
We get rid of parentheses
-32k-4+132=0
We add all the numbers together, and all the variables
-32k+128=0
We move all terms containing k to the left, all other terms to the right
-32k=-128
k=-128/-32
k=+4

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