3(z-7)+2z-4=5(z-5)

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Solution for 3(z-7)+2z-4=5(z-5) equation: 



3(z-7)+2z-4=5(z-5)

We move all terms to the left:

3(z-7)+2z-4-(5(z-5))=0

We add all the numbers together, and all the variables

2z+3(z-7)-(5(z-5))-4=0

We multiply parentheses

2z+3z-(5(z-5))-21-4=0



We calculate terms in parentheses: -(5(z-5)), so:

5(z-5)

We multiply parentheses

5z-25

Back to the equation:

-(5z-25)



We add all the numbers together, and all the variables

5z-(5z-25)-25=0

We get rid of parentheses

5z-5z+25-25=0

We add all the numbers together, and all the variables

=0

z=0/1

z=0

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