13/12(3x)=32

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Solution for 13/12(3x)=32 equation: 



13/12(3x)=32

We move all terms to the left:

13/12(3x)-(32)=0



Domain of the equation: 123x!=0

x!=0/123

x!=0

x∈R



We multiply all the terms by the denominator


-32*123x+13=0

Wy multiply elements

-3936x+13=0

We move all terms containing x to the left, all other terms to the right

-3936x=-13

x=-13/-3936

x=13/3936

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