13/12(2x+x)=32

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Solution for 13/12(2x+x)=32 equation: 



13/12(2x+x)=32

We move all terms to the left:

13/12(2x+x)-(32)=0



Domain of the equation: 12(2x+x)!=0

x∈R



We add all the numbers together, and all the variables

13/12(+3x)-32=0

We multiply all the terms by the denominator


-32*12(+3x)+13=0

Wy multiply elements

-384x(++13=0

We use the square of the difference formula

-384x(+13=0

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