13-2(3b+4)=3(b+2)

Solution for 13-2(3b+4)=3(b+2) equation:

13-2(3b+4)=3(b+2)

We move all terms to the left:

13-2(3b+4)-(3(b+2))=0

We multiply parentheses

-6b-(3(b+2))-8+13=0


We calculate terms in parentheses: -(3(b+2)), so:

3(b+2)

We multiply parentheses

3b+6

Back to the equation:

-(3b+6)


We add all the numbers together, and all the variables

-6b-(3b+6)+5=0

We get rid of parentheses

-6b-3b-6+5=0

We add all the numbers together, and all the variables

-9b-1=0

We move all terms containing b to the left, all other terms to the right

-9b=1

b=1/-9

b=-1/9