2(d-25)+3=d+28

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Solution for 2(d-25)+3=d+28 equation: 



2(d-25)+3=d+28

We move all terms to the left:

2(d-25)+3-(d+28)=0

We multiply parentheses

2d-(d+28)-50+3=0

We get rid of parentheses

2d-d-28-50+3=0

We add all the numbers together, and all the variables

d-75=0

We move all terms containing d to the left, all other terms to the right

d=75

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