13-(2y-1)=2(y-1)+4

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Solution for 13-(2y-1)=2(y-1)+4 equation: 



13-(2y-1)=2(y-1)+4

We move all terms to the left:

13-(2y-1)-(2(y-1)+4)=0

We get rid of parentheses

-2y-(2(y-1)+4)+1+13=0



We calculate terms in parentheses: -(2(y-1)+4), so:

2(y-1)+4

We multiply parentheses

2y-2+4

We add all the numbers together, and all the variables

2y+2

Back to the equation:

-(2y+2)



We add all the numbers together, and all the variables

-2y-(2y+2)+14=0

We get rid of parentheses

-2y-2y-2+14=0

We add all the numbers together, and all the variables

-4y+12=0

We move all terms containing y to the left, all other terms to the right

-4y=-12

y=-12/-4

y=+3

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