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-(2Q+1)=8-(3Q+3)
We move all terms to the left:
-(2Q+1)-(8-(3Q+3))=0
We get rid of parentheses
-2Q-(8-(3Q+3))-1=0
We calculate terms in parentheses: -(8-(3Q+3)), so:We get rid of parentheses
8-(3Q+3)
determiningTheFunctionDomain -(3Q+3)+8
We get rid of parentheses
-3Q-3+8
We add all the numbers together, and all the variables
-3Q+5
Back to the equation:
-(-3Q+5)
-2Q+3Q-5-1=0
We add all the numbers together, and all the variables
Q-6=0
We move all terms containing Q to the left, all other terms to the right
Q=6
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