13-(2c+2)+2(c+2)=3c

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Solution for 13-(2c+2)+2(c+2)=3c equation:


Simplifying
13 + -1(2c + 2) + 2(c + 2) = 3c

Reorder the terms:
13 + -1(2 + 2c) + 2(c + 2) = 3c
13 + (2 * -1 + 2c * -1) + 2(c + 2) = 3c
13 + (-2 + -2c) + 2(c + 2) = 3c

Reorder the terms:
13 + -2 + -2c + 2(2 + c) = 3c
13 + -2 + -2c + (2 * 2 + c * 2) = 3c
13 + -2 + -2c + (4 + 2c) = 3c

Reorder the terms:
13 + -2 + 4 + -2c + 2c = 3c

Combine like terms: 13 + -2 = 11
11 + 4 + -2c + 2c = 3c

Combine like terms: 11 + 4 = 15
15 + -2c + 2c = 3c

Combine like terms: -2c + 2c = 0
15 + 0 = 3c
15 = 3c

Solving
15 = 3c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-3c' to each side of the equation.
15 + -3c = 3c + -3c

Combine like terms: 3c + -3c = 0
15 + -3c = 0

Add '-15' to each side of the equation.
15 + -15 + -3c = 0 + -15

Combine like terms: 15 + -15 = 0
0 + -3c = 0 + -15
-3c = 0 + -15

Combine like terms: 0 + -15 = -15
-3c = -15

Divide each side by '-3'.
c = 5

Simplifying
c = 5

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