7/10=(d+4)/(2d)

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Solution for 7/10=(d+4)/(2d) equation: 


D( d )

2*d = 0

2*d = 0

2*d = 0

2*d = 0 // : 2

d = 0

d in (-oo:0) U (0:+oo)

7/10 = (d+4)/(2*d) // - (d+4)/(2*d)

7/10-((d+4)/(2*d)) = 0

(-1*(d+4))/(2*d)+7/10 = 0

(-1*10*(d+4))/(2*10*d)+(2*7*d)/(2*10*d) = 0

2*7*d-1*10*(d+4) = 0

4*d-40 = 0

(4*d-40)/(2*10*d) = 0

(4*d-40)/(2*10*d) = 0 // * 2*10*d

4*d-40 = 0

4*d-40 = 0 // + 40

4*d = 40 // : 4

d = 40/4

d = 10

d = 10

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