13-(2c+12)=2(c+12)+3c

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Solution for 13-(2c+12)=2(c+12)+3c equation:



13-(2c+12)=2(c+12)+3c
We move all terms to the left:
13-(2c+12)-(2(c+12)+3c)=0
We get rid of parentheses
-2c-(2(c+12)+3c)-12+13=0
We calculate terms in parentheses: -(2(c+12)+3c), so:
2(c+12)+3c
We add all the numbers together, and all the variables
3c+2(c+12)
We multiply parentheses
3c+2c+24
We add all the numbers together, and all the variables
5c+24
Back to the equation:
-(5c+24)
We add all the numbers together, and all the variables
-2c-(5c+24)+1=0
We get rid of parentheses
-2c-5c-24+1=0
We add all the numbers together, and all the variables
-7c-23=0
We move all terms containing c to the left, all other terms to the right
-7c=23
c=23/-7
c=-3+2/7

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