13-(2c+12)=2(c+12)-3c

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Solution for 13-(2c+12)=2(c+12)-3c equation: 



13-(2c+12)=2(c+12)-3c

We move all terms to the left:

13-(2c+12)-(2(c+12)-3c)=0

We get rid of parentheses

-2c-(2(c+12)-3c)-12+13=0



We calculate terms in parentheses: -(2(c+12)-3c), so:

2(c+12)-3c

We add all the numbers together, and all the variables

-3c+2(c+12)

We multiply parentheses

-3c+2c+24

We add all the numbers together, and all the variables

-1c+24

Back to the equation:

-(-1c+24)



We add all the numbers together, and all the variables

-2c-(-1c+24)+1=0

We get rid of parentheses

-2c+1c-24+1=0

We add all the numbers together, and all the variables

-1c-23=0

We move all terms containing c to the left, all other terms to the right

-c=23

c=23/-1

c=-23

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