13+9k-4=2(k-6)

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Solution for 13+9k-4=2(k-6) equation: 



13+9k-4=2(k-6)

We move all terms to the left:

13+9k-4-(2(k-6))=0

We add all the numbers together, and all the variables

9k-(2(k-6))+9=0



We calculate terms in parentheses: -(2(k-6)), so:

2(k-6)

We multiply parentheses

2k-12

Back to the equation:

-(2k-12)



We get rid of parentheses

9k-2k+12+9=0

We add all the numbers together, and all the variables

7k+21=0

We move all terms containing k to the left, all other terms to the right

7k=-21

k=-21/7

k=-3

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