(20-12=)6-5(5a-3)

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Solution for (20-12=)6-5(5a-3) equation: 



(20-12=)6-5(5a-3)

We move all terms to the left:

(20-12-()6-5(5a-3))=0



We calculate terms in parentheses: +(20-12-()6-5(5a-3)), so:

20-12-()6-5(5a-3)

determiningTheFunctionDomain
-5(5a-3)+20-12-()6

We add all the numbers together, and all the variables

-5(5a-3)

We multiply parentheses

-25a+15

Back to the equation:

+(-25a+15)



We get rid of parentheses

-25a+15=0

We move all terms containing a to the left, all other terms to the right

-25a=-15

a=-15/-25

a=3/5

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