13+4x=3(-x+6)-40

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Solution for 13+4x=3(-x+6)-40 equation: 



13+4x=3(-x+6)-40

We move all terms to the left:

13+4x-(3(-x+6)-40)=0

We add all the numbers together, and all the variables

4x-(3(-1x+6)-40)+13=0



We calculate terms in parentheses: -(3(-1x+6)-40), so:

3(-1x+6)-40

We multiply parentheses

-3x+18-40

We add all the numbers together, and all the variables

-3x-22

Back to the equation:

-(-3x-22)



We get rid of parentheses

4x+3x+22+13=0

We add all the numbers together, and all the variables

7x+35=0

We move all terms containing x to the left, all other terms to the right

7x=-35

x=-35/7

x=-5

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