8x+3(6x-4)=2+7(3x-2)+5x

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Solution for 8x+3(6x-4)=2+7(3x-2)+5x equation:



8x+3(6x-4)=2+7(3x-2)+5x
We move all terms to the left:
8x+3(6x-4)-(2+7(3x-2)+5x)=0
We multiply parentheses
8x+18x-(2+7(3x-2)+5x)-12=0
We calculate terms in parentheses: -(2+7(3x-2)+5x), so:
2+7(3x-2)+5x
determiningTheFunctionDomain 7(3x-2)+5x+2
We add all the numbers together, and all the variables
5x+7(3x-2)+2
We multiply parentheses
5x+21x-14+2
We add all the numbers together, and all the variables
26x-12
Back to the equation:
-(26x-12)
We add all the numbers together, and all the variables
26x-(26x-12)-12=0
We get rid of parentheses
26x-26x+12-12=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0

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