13+2(x-6)=19-3(x+1)

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Solution for 13+2(x-6)=19-3(x+1) equation: 



13+2(x-6)=19-3(x+1)

We move all terms to the left:

13+2(x-6)-(19-3(x+1))=0

We multiply parentheses

2x-(19-3(x+1))-12+13=0



We calculate terms in parentheses: -(19-3(x+1)), so:

19-3(x+1)

determiningTheFunctionDomain
-3(x+1)+19

We multiply parentheses

-3x-3+19

We add all the numbers together, and all the variables

-3x+16

Back to the equation:

-(-3x+16)



We add all the numbers together, and all the variables

2x-(-3x+16)+1=0

We get rid of parentheses

2x+3x-16+1=0

We add all the numbers together, and all the variables

5x-15=0

We move all terms containing x to the left, all other terms to the right

5x=15

x=15/5

x=3

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