13+2(3f-6)=1+6f

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Solution for 13+2(3f-6)=1+6f equation: 



13+2(3f-6)=1+6f

We move all terms to the left:

13+2(3f-6)-(1+6f)=0

We add all the numbers together, and all the variables

2(3f-6)-(6f+1)+13=0

We multiply parentheses

6f-(6f+1)-12+13=0

We get rid of parentheses

6f-6f-1-12+13=0

We add all the numbers together, and all the variables

=0

f=0/1

f=0

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