5(1h+5)+7=1h+4(1h+4)+16

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Solution for 5(1h+5)+7=1h+4(1h+4)+16 equation:



5(1h+5)+7=1h+4(1h+4)+16
We move all terms to the left:
5(1h+5)+7-(1h+4(1h+4)+16)=0
We add all the numbers together, and all the variables
5(h+5)-(1h+4(h+4)+16)+7=0
We multiply parentheses
5h-(1h+4(h+4)+16)+25+7=0
We calculate terms in parentheses: -(1h+4(h+4)+16), so:
1h+4(h+4)+16
We add all the numbers together, and all the variables
h+4(h+4)+16
We multiply parentheses
h+4h+16+16
We add all the numbers together, and all the variables
5h+32
Back to the equation:
-(5h+32)
We add all the numbers together, and all the variables
5h-(5h+32)+32=0
We get rid of parentheses
5h-5h-32+32=0
We add all the numbers together, and all the variables
=0
h=0/1
h=0

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