13(z+6)=4(z-3)-5z

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Solution for 13(z+6)=4(z-3)-5z equation: 



13(z+6)=4(z-3)-5z

We move all terms to the left:

13(z+6)-(4(z-3)-5z)=0

We multiply parentheses

13z-(4(z-3)-5z)+78=0



We calculate terms in parentheses: -(4(z-3)-5z), so:

4(z-3)-5z

We add all the numbers together, and all the variables

-5z+4(z-3)

We multiply parentheses

-5z+4z-12

We add all the numbers together, and all the variables

-1z-12

Back to the equation:

-(-1z-12)



We get rid of parentheses

13z+1z+12+78=0

We add all the numbers together, and all the variables

14z+90=0

We move all terms containing z to the left, all other terms to the right

14z=-90

z=-90/14

z=-6+3/7

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