13(x+4)-2(x-3)=5(x-1)+5(x-1)

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Solution for 13(x+4)-2(x-3)=5(x-1)+5(x-1) equation: 



13(x+4)-2(x-3)=5(x-1)+5(x-1)

We move all terms to the left:

13(x+4)-2(x-3)-(5(x-1)+5(x-1))=0

We multiply parentheses

13x-2x-(5(x-1)+5(x-1))+52+6=0



We calculate terms in parentheses: -(5(x-1)+5(x-1)), so:

5(x-1)+5(x-1)

We multiply parentheses

5x+5x-5-5

We add all the numbers together, and all the variables

10x-10

Back to the equation:

-(10x-10)



We add all the numbers together, and all the variables

11x-(10x-10)+58=0

We get rid of parentheses

11x-10x+10+58=0

We add all the numbers together, and all the variables

x+68=0

We move all terms containing x to the left, all other terms to the right

x=-68

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