3(3x-5)-3=3(x-3)+21

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Solution for 3(3x-5)-3=3(x-3)+21 equation: 



3(3x-5)-3=3(x-3)+21

We move all terms to the left:

3(3x-5)-3-(3(x-3)+21)=0

We multiply parentheses

9x-(3(x-3)+21)-15-3=0



We calculate terms in parentheses: -(3(x-3)+21), so:

3(x-3)+21

We multiply parentheses

3x-9+21

We add all the numbers together, and all the variables

3x+12

Back to the equation:

-(3x+12)



We add all the numbers together, and all the variables

9x-(3x+12)-18=0

We get rid of parentheses

9x-3x-12-18=0

We add all the numbers together, and all the variables

6x-30=0

We move all terms containing x to the left, all other terms to the right

6x=30

x=30/6

x=5

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