12y-9=6(y+3)+3y

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Solution for 12y-9=6(y+3)+3y equation: 



12y-9=6(y+3)+3y

We move all terms to the left:

12y-9-(6(y+3)+3y)=0



We calculate terms in parentheses: -(6(y+3)+3y), so:

6(y+3)+3y

We add all the numbers together, and all the variables

3y+6(y+3)

We multiply parentheses

3y+6y+18

We add all the numbers together, and all the variables

9y+18

Back to the equation:

-(9y+18)



We get rid of parentheses

12y-9y-18-9=0

We add all the numbers together, and all the variables

3y-27=0

We move all terms containing y to the left, all other terms to the right

3y=27

y=27/3

y=9

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