4(3a+5)=7a+40

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Solution for 4(3a+5)=7a+40 equation: 



4(3a+5)=7a+40

We move all terms to the left:

4(3a+5)-(7a+40)=0

We multiply parentheses

12a-(7a+40)+20=0

We get rid of parentheses

12a-7a-40+20=0

We add all the numbers together, and all the variables

5a-20=0

We move all terms containing a to the left, all other terms to the right

5a=20

a=20/5

a=4

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