12y-62=-8(y-22)

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Solution for 12y-62=-8(y-22) equation: 



12y-62=-8(y-22)

We move all terms to the left:

12y-62-(-8(y-22))=0



We calculate terms in parentheses: -(-8(y-22)), so:

-8(y-22)

We multiply parentheses

-8y+176

Back to the equation:

-(-8y+176)



We get rid of parentheses

12y+8y-176-62=0

We add all the numbers together, and all the variables

20y-238=0

We move all terms containing y to the left, all other terms to the right

20y=238

y=238/20

y=11+9/10

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