12y-5(3y-2)=0

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Solution for 12y-5(3y-2)=0 equation: 



12y-5(3y-2)=0

We multiply parentheses

12y-15y+10=0

We add all the numbers together, and all the variables

-3y+10=0

We move all terms containing y to the left, all other terms to the right

-3y=-10

y=-10/-3

y=3+1/3

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