12y-3(y-2)=3(y+4)

Solution for 12y-3(y-2)=3(y+4) equation:

12y-3(y-2)=3(y+4)

We move all terms to the left:

12y-3(y-2)-(3(y+4))=0

We multiply parentheses

12y-3y-(3(y+4))+6=0


We calculate terms in parentheses: -(3(y+4)), so:

3(y+4)

We multiply parentheses

3y+12

Back to the equation:

-(3y+12)


We add all the numbers together, and all the variables

9y-(3y+12)+6=0

We get rid of parentheses

9y-3y-12+6=0

We add all the numbers together, and all the variables

6y-6=0

We move all terms containing y to the left, all other terms to the right

6y=6

y=6/6

y=1