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(2x+3)(3x-1)=(6x-1)(x-2)
We move all terms to the left:
(2x+3)(3x-1)-((6x-1)(x-2))=0
We multiply parentheses ..
(+6x^2-2x+9x-3)-((6x-1)(x-2))=0
We calculate terms in parentheses: -((6x-1)(x-2)), so:We get rid of parentheses
(6x-1)(x-2)
We multiply parentheses ..
(+6x^2-12x-1x+2)
We get rid of parentheses
6x^2-12x-1x+2
We add all the numbers together, and all the variables
6x^2-13x+2
Back to the equation:
-(6x^2-13x+2)
6x^2-6x^2-2x+9x+13x-3-2=0
We add all the numbers together, and all the variables
20x-5=0
We move all terms containing x to the left, all other terms to the right
20x=5
x=5/20
x=1/4
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