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12x^2-7x=39
We move all terms to the left:
12x^2-7x-(39)=0
a = 12; b = -7; c = -39;
Δ = b2-4ac
Δ = -72-4·12·(-39)
Δ = 1921
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{1921}}{2*12}=\frac{7-\sqrt{1921}}{24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{1921}}{2*12}=\frac{7+\sqrt{1921}}{24} $
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