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0=y2-6y+9
We move all terms to the left:
0-(y2-6y+9)=0
We add all the numbers together, and all the variables
-(+y^2-6y+9)+0=0
We add all the numbers together, and all the variables
-(+y^2-6y+9)=0
We get rid of parentheses
-y^2+6y-9=0
We add all the numbers together, and all the variables
-1y^2+6y-9=0
a = -1; b = 6; c = -9;
Δ = b2-4ac
Δ = 62-4·(-1)·(-9)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$y=\frac{-b}{2a}=\frac{-6}{-2}=+3$
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