12x2+104x+105=(6x+7)(2x+15)

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Solution for 12x2+104x+105=(6x+7)(2x+15) equation: 



12x^2+104x+105=(6x+7)(2x+15)

We move all terms to the left:

12x^2+104x+105-((6x+7)(2x+15))=0

We multiply parentheses ..

12x^2-((+12x^2+90x+14x+105))+104x+105=0



We calculate terms in parentheses: -((+12x^2+90x+14x+105)), so:

(+12x^2+90x+14x+105)

We get rid of parentheses

12x^2+90x+14x+105

We add all the numbers together, and all the variables

12x^2+104x+105

Back to the equation:

-(12x^2+104x+105)



We add all the numbers together, and all the variables

12x^2+104x-(12x^2+104x+105)+105=0

We get rid of parentheses

12x^2-12x^2+104x-104x-105+105=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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