12x-7=3(x-5)-28

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Solution for 12x-7=3(x-5)-28 equation: 



12x-7=3(x-5)-28

We move all terms to the left:

12x-7-(3(x-5)-28)=0



We calculate terms in parentheses: -(3(x-5)-28), so:

3(x-5)-28

We multiply parentheses

3x-15-28

We add all the numbers together, and all the variables

3x-43

Back to the equation:

-(3x-43)



We get rid of parentheses

12x-3x+43-7=0

We add all the numbers together, and all the variables

9x+36=0

We move all terms containing x to the left, all other terms to the right

9x=-36

x=-36/9

x=-4

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