(x+30)+(x-35)=75+130+(x-5)

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Solution for (x+30)+(x-35)=75+130+(x-5) equation: 



(x+30)+(x-35)=75+130+(x-5)

We move all terms to the left:

(x+30)+(x-35)-(75+130+(x-5))=0

We get rid of parentheses

x+x-(75+130+(x-5))+30-35=0



We calculate terms in parentheses: -(75+130+(x-5)), so:

75+130+(x-5)

determiningTheFunctionDomain
(x-5)+75+130

We add all the numbers together, and all the variables

(x-5)+205

We get rid of parentheses

x-5+205

We add all the numbers together, and all the variables

x+200

Back to the equation:

-(x+200)



We add all the numbers together, and all the variables

2x-(x+200)-5=0

We get rid of parentheses

2x-x-200-5=0

We add all the numbers together, and all the variables

x-205=0

We move all terms containing x to the left, all other terms to the right

x=205

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