12x-4+(4x+8)/6=x/3+(18x+1)/3

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Solution for 12x-4+(4x+8)/6=x/3+(18x+1)/3 equation:


x in (-oo:+oo)

(4*x+8)/6+12*x-4 = (18*x+1)/3+x/3 // - (18*x+1)/3+x/3

(4*x+8)/6-((18*x+1)/3)+12*x-(x/3)-4 = 0

(4*x+8)/6+(-1*(18*x+1))/3+12*x-x/3-4 = 0

(3*(4*x+8))/(3*6)+(-1*6*(18*x+1))/(3*6)+(3*6*12*x)/(3*6)+(6*(-x))/(3*6)+(-4*3*6)/(3*6) = 0

3*(4*x+8)-1*6*(18*x+1)+3*6*12*x+6*(-x)-4*3*6 = 0

216*x-96*x-6*x-72+18 = 0

120*x-6*x-72+18 = 0

114*x-72+18 = 0

114*x-54 = 0

(114*x-54)/(3*6) = 0

(114*x-54)/(3*6) = 0 // * 3*6

114*x-54 = 0

114*x-54 = 0 // + 54

114*x = 54 // : 114

x = 54/114

x = 9/19

x = 9/19

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