(4n+2)/3=(2n-1)/3

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Solution for (4n+2)/3=(2n-1)/3 equation: 


n in (-oo:+oo)

(4*n+2)/3 = (2*n-1)/3 // - (2*n-1)/3

(4*n+2)/3-((2*n-1)/3) = 0

(4*n+2)/3+(-1*(2*n-1))/3 = 0

4*n-1*(2*n-1)+2 = 0

2*n+3 = 0

(2*n+3)/3 = 0

(2*n+3)/3 = 0 // * 3

2*n+3 = 0

2*n+3 = 0 // - 3

2*n = -3 // : 2

n = -3/2

n = -3/2

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