12x-19=(4x-6)+(x+1)

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Solution for 12x-19=(4x-6)+(x+1) equation: 



12x-19=(4x-6)+(x+1)

We move all terms to the left:

12x-19-((4x-6)+(x+1))=0



We calculate terms in parentheses: -((4x-6)+(x+1)), so:

(4x-6)+(x+1)

We get rid of parentheses

4x+x-6+1

We add all the numbers together, and all the variables

5x-5

Back to the equation:

-(5x-5)



We get rid of parentheses

12x-5x+5-19=0

We add all the numbers together, and all the variables

7x-14=0

We move all terms containing x to the left, all other terms to the right

7x=14

x=14/7

x=2

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