5=(4x-4)+(x+1)

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Solution for 5=(4x-4)+(x+1) equation: 



5=(4x-4)+(x+1)

We move all terms to the left:

5-((4x-4)+(x+1))=0



We calculate terms in parentheses: -((4x-4)+(x+1)), so:

(4x-4)+(x+1)

We get rid of parentheses

4x+x-4+1

We add all the numbers together, and all the variables

5x-3

Back to the equation:

-(5x-3)



We get rid of parentheses

-5x+3+5=0

We add all the numbers together, and all the variables

-5x+8=0

We move all terms containing x to the left, all other terms to the right

-5x=-8

x=-8/-5

x=1+3/5

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