12x-15=x(4x+5)

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Solution for 12x-15=x(4x+5) equation: 



12x-15=x(4x+5)

We move all terms to the left:

12x-15-(x(4x+5))=0



We calculate terms in parentheses: -(x(4x+5)), so:

x(4x+5)

We multiply parentheses

4x^2+5x

Back to the equation:

-(4x^2+5x)



We get rid of parentheses

-4x^2+12x-5x-15=0

We add all the numbers together, and all the variables

-4x^2+7x-15=0

a = -4; b = 7; c = -15;
Δ = b2-4ac
Δ = 72-4·(-4)·(-15)
Δ = -191
Delta is less than zero, so there is no solution for the equation

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